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0.75x^2=12
We move all terms to the left:
0.75x^2-(12)=0
a = 0.75; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·0.75·(-12)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*0.75}=\frac{-6}{1.5} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*0.75}=\frac{6}{1.5} =4 $
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